It has limitations. That's the reason calculus exists (not the sole reason though). Things like limits are needed specifically to address problems for which algebra doesn't define a solution.
Of course, it has nothing to do with what the OP posted.
Can you prove 1 = 2?
- Thread starter secondeye
- Start date
It has limitations. That's the reason calculus exists (not the sole reason though). Things like limits are needed specifically to address problems for which algebra doesn't define a solution.
Of course, it has nothing to do with what the OP posted.
Although I don't think it's what you meant, order of operations should also be considered.
3-3/3-3 = 3-1-3 = -1
(3-3)/(3-3) is not equal to 0/0, it is indeterminate; whereas (x-y)/(x-y)=1 for all real numbers, such that x != y.
I think maybe this one is supposed to be a joke.
Here's a better problem for those getting ready to get into calculus; it's one of Zeno's paradoxes:
alas:
x = y
x+x-x = y+y-y
Given x = y, this can be written as:
x+x-x = x+x-x
And shortened to
x+0 = x+0 (added for clarity)
x = x
Q.E.D
Of course, if you need to preserve y, you can still shorten it
x+x-x = y+y-y
x+0 = y+0
x = y
Never trust an equation where someone does not shorten correctly.
::emp::
Another way to prove algebraically....
Let a = b
=> a2 = ab
=> a2 + a2 = a2 + ab
=> 2a2 = a2 + ab
=> 2a2 – 2ab = a2 + ab – 2ab
=> 2a2 - 2ab = a2 - ab
=> 2(a2 – ab) = 1(a2 - ab)
Canceling the (a2 - ab)
It gives 1 = 2
Hope it would work...........
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Let a = b
=> a2 = ab
=> a2 + a2 = a2 + ab
=> 2a2 = a2 + ab
=> 2a2 – 2ab = a2 + ab – 2ab
=> 2a2 - 2ab = a2 - ab
=> 2(a2 – ab) = 1(a2 - ab)
Canceling the (a2 - ab)
It gives 1 = 2
Hope it would work...........
______________________
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hey my sister is pregnant and she is now 1 but equal to 2 so, 1 = 2....lol
not of offend anyone but thought would share this
not of offend anyone but thought would share this
Another fail due to shitty notation
Let a = b
=> a2 = ab ¦ + ab
=> a2 + a2 = a2 + ab ¦*2 (or where else are you getting the 2 in front?
=> 2a2 = a2 + ab
=> 2a2 + 2a2 = 2a2 + 2ab
=> 4a + 4a = 4a + 2ab ¦ ab = 2a, such that
=> 4a +4a = 4a + 2a*2a
=> 8a = 8a
Also, don't fuck with the number / variable sorting. It is 2a, not a2 :ugone2far:
Written like this:
Let a=b
-> 2a = ab ¦+ab
-> 2a + ab = ab + ab ¦*2
-> 4a + 2ab = 2ab + 2ab
-> 4a + 4a = 4ab
-> 8a = 4ab
-> 8a = 8a
blargh.. it becomes apparent that there is no 1=2.
::emp::
Sorry.... u have misinterpreted it......... a2 means (a)square or you can say "a" to the power "2"...............
I am not that crazy .......will write 2a as a2.............
Newaz it's my mistake..... i would have denoted it correctly.........
Hope you will get it now.........
a2 + a2 = 2a2 (it means a^2 + a^2 = 2a^2)
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2(a^2 – ab) = 1(a^2 - ab)
This is a similar mistake to stating (x-y)/(x-y)=1 when x=y
The only way you can get to this line is by making a=b, which you stated explicitly on the first line. If a=b and a^2=ab (which is your line 2), then a^2-ab = 0. Order of operations (arithmetic) states that operations in parenthesis must be done first, so assuming a and b are defined for all real numbers, the next line would be:
2(0)=1(0)
0=0